In this series, Pulkit Chhabra, an avid programmer from DTU with offers from Amazon, Goldman Sachs & Codenation and master on Codeforces, discusses solution/approach to problem 1327-C, Game with Chips of Codeforces Global Round 84 held on 23 March 2020

The series will cover solutions to all problems from A to E

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11 Comments

  • Ifran 07
    Posted May 11, 2020 9:47 pm

    😍

  • PRAKHAR SHEKHAR PARTHASARTHI
    Posted May 11, 2020 9:47 pm

    sir, I follow your code and I can't understand the meaning of some lines in your code
    Please explain the purpose of these lines———————————————————–
    1) mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
    2) #define pw(b,p) pow(b,p) + 0.1
    (why pow + 0.1 ???)

    3) #define ps(x,y) fixed<<setprecision(y)<<x
    4) ios_base::sync_with_stdio(0); cin.tie(0); cout.tie(0);

  • Sunny Sinha
    Posted May 11, 2020 9:47 pm

    arrey bahut kharab lag gaya solution dekh kar… ban sakta thha

  • Samad Khan
    Posted May 11, 2020 9:47 pm

    Sir in the problem it is given
    If the chip was in the (x,y) cell, then after the operation:

    left, its coordinates will be (x,y−1);
    right, its coordinates will be (x,y+1);
    down, its coordinates will be (x+1,y);
    up, its coordinates will be (x−1,y).

    Then to go LEFT why we are not using "U"; Same for RIGHT we should use "D"

  • Dhruvil Patel
    Posted May 11, 2020 9:47 pm

    please continue this process of discussing codeforces solutions regularly. Thanks for the solution.

  • Impulse
    Posted May 11, 2020 9:47 pm

    waiting for problem E 🙂

  • Bhanu Pratap Singh
    Posted May 11, 2020 9:47 pm

    please upload the solution of E. Count The Blocks also

  • jeet ganatra
    Posted May 11, 2020 9:47 pm

    Excellent approach !!

  • Rakesh Gupta
    Posted May 11, 2020 9:47 pm

    Very clear solution. Thanks a lot!

  • Saksham Sethi
    Posted May 11, 2020 9:47 pm

    This is problem C

  • Tanishq Gupta
    Posted May 11, 2020 9:47 pm

    Bhaiya this is problem c not problem b

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